From the abbreviated name of the compound Gal(β1 → 4)Glc, we know that:
A) C-4 of glucose is joined to C-1 of galactose by a glycosidic bond.
B) the compound is a D-enantiomer.
C) the galactose residue is at the reducing end.
D) the glucose is in its pyranose form.
E) the glucose residue is the β anomer.
Answer: A) C-4 of glucose is joined to C-1 of galactose by a glycosidic bond.