Consider a population of fish where the length of a given fish's dorsal spine is determined by a single gene, which is defined by two different alleles. The dominant A allele encodes a long dorsal spine and the recessive a allele encodes a short dorsal spine. The fish is diploid and reproduces sexually. The number of AA individuals in this population is 500, the number of Aa individuals is 100, and the number of aa individuals is 400. If a new population was started with 10 AA, 20 Aa, and 10 aa fish, then what are the new allelic frequencies?
A - 60% A and 40% a
B - 40% A and 60% a
C - 50% A and 50% a
D - 75% A and 25% a
Answer: C - 50% A and 50% a
To solve this problem you would use the equations:
p=B/B+b and q=b/B+b